I’d happily like to share them here by courtesy Sumit Raj:
Trick #1
Reversing a string in Python
- >>> a = "codementor"
- >>> print "Reverse is",a[::-1]
- Reverse is rotnemedoc
Trick #2
Transposing a Matrix
- >>> mat = [[1, 2, 3], [4, 5, 6]]
- >>> zip(*mat)
- [(1, 4), (2, 5), (3, 6)]
Trick #3
a = [1,2,3]
Store all three values of the list in 3 new variables
- >>> a = [1, 2, 3]
- >>> x, y, z = a
- >>> x
- 1
- >>> y
- 2
- >>> z
- 3
Trick #4
a = ["Code", "mentor", "Python", "Developer"]
Create a single string from all the elements in list above.
- >>> print " ".join(a)
- Code mentor Python Developer
Trick #5
List 1 = ['a', 'b', 'c', 'd']
List 2 = ['p', 'q', 'r', 's']
Write a Python code to print
- ap
- bq
- cr
- ds
- >>> for x, y in zip(list1,list2):
- ... print x, y
- ...
- a p
- b q
- c r
- d s
Trick #6
Swap two numbers with one line of code.
- >>> a=7
- >>> b=5
- >>> b, a =a, b
- >>> a
- 5
- >>> b
- 7
Trick #7
Print "codecodecodecode mentormentormentormentormentor" without using loops
- >>> print "code"*4+' '+"mentor"*5
- codecodecodecode mentormentormentormentormentor
Trick #8
a = [[1, 2], [3, 4], [5, 6]]
Convert it to a single list without using any loops.
Output:- [1, 2, 3, 4, 5, 6]
- >>> import itertools
- >>> list(itertools.chain.from_iterable(a))
- [1, 2, 3, 4, 5, 6]
Trick #9
Checking if two words are anagrams
- def is_anagram(word1, word2):
- """Checks whether the words are anagrams.
- word1: string
- word2: string
- returns: boolean
- """
Complete the above method to find if two words are anagrams.
- from collections import Counter
- def is_anagram(str1, str2):
- return Counter(str1) == Counter(str2)
- >>> is_anagram('abcd','dbca')
- True
- >>> is_anagram('abcd','dbaa')
- False
Trick #10.
Taking a string input.
For example "1 2 3 4" and return [1, 2, 3, 4]
Remember list being returned has integers in it.
Don't use more than one line of code.
Don't use more than one line of code.
- >>> result = map(lambda x:int(x) ,raw_input().split())
- 1 2 3 4
- >>> result
- [1, 2, 3, 4]
Footnotes